Question

subtract and simplify:
b/s+b - b/s-b

Answer 1

(b(s-b) - b(s+b)) / ((s+b)(s-b))

-2b^2 / ((s+b)(s-b))

Answer 2

find a common denominator. mul
[b(s-b)]/[(s+b)(s-b)]-[b(s+b)/(s-b)(s+b)]


[(bs-b^2)/(s^2-b^2)]-[(bs+b^2)/(s^2-b^2)]

Now that there is a common denominator subtract the numerators.

(bs-b^2)-(bs+b^2) *distribute the main subtraction operator two the expression on the right*

bs-b^2-bs-b^2 = -2b^2 (final numerator value)

Take the final numerator value and put it back with the final denominator value of s^2-b^2...

(-2b^2)/(s^2-b^2) *note the -b^2 in the denominator cannot be factored out.