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differentiate f(x)=sec^4(3x^2)
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please tell me that is not a power in a power and that the sec is multiplied by the (3x^2)
sec to the 4 power (3x^2)
no
sec(3x^2)^4
\[\sec ^{4}\left( 3x ^{2} \right)\]
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oh, damn notation lol
chainn rule ftwww, do the 5th power than treat your sec of blah as the inside, you will have to use the power rule again for the blah
so: sec(blah)^4 : 4(sec(blah)^3)*(sec') your sec' is also going to use the chain rule where sec'(blah) = sec(blah)tan(blah) * (blah') where your blah is going to be the "3x^2)
hence you get: 4(sec3(3x^2)*sec(3x^2)(tan(3x^2)*6x
好了吗?
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yeaa i got u,, lol, blah
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