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Mathematics 7 Online
OpenStudy (anonymous):

differentiate f(x)=sec^4(3x^2)

OpenStudy (anonymous):

please tell me that is not a power in a power and that the sec is multiplied by the (3x^2)

OpenStudy (anonymous):

sec to the 4 power (3x^2)

OpenStudy (anonymous):

no

OpenStudy (anonymous):

sec(3x^2)^4

OpenStudy (anonymous):

\[\sec ^{4}\left( 3x ^{2} \right)\]

OpenStudy (anonymous):

oh, damn notation lol

OpenStudy (anonymous):

chainn rule ftwww, do the 5th power than treat your sec of blah as the inside, you will have to use the power rule again for the blah

OpenStudy (anonymous):

so: sec(blah)^4 : 4(sec(blah)^3)*(sec') your sec' is also going to use the chain rule where sec'(blah) = sec(blah)tan(blah) * (blah') where your blah is going to be the "3x^2)

OpenStudy (anonymous):

hence you get: 4(sec3(3x^2)*sec(3x^2)(tan(3x^2)*6x

OpenStudy (anonymous):

好了吗?

OpenStudy (anonymous):

yeaa i got u,, lol, blah

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