Question

can u check if i am right? differentiate f(x)=x^2e^-3x

Answer 1

f'(x)=2xe^-3x-3x^2e^-3x

Answer 2

more clear

Answer 3

f'(x)=(2x e^-3x)-(3x^2 e^-3x)

Answer 4

\[f(x)=x^2e^{-3x}\]

Answer 5

yes

Answer 6

product rule problem.
\[(fg)'=f'g+g'f\] use
\[f(x)=x^2,f'(x)-2x,g(x)=e^{-3x},g'(x)=-3e^{-3x}\]

Answer 7

so im right

Answer 8

gives
\[2xe^{-3x}-3x^2e^{-3x}\]

Answer 9

yes you are right.

Answer 10

OHHHHH i thought it was \[f(x)=x ^{2e ^{-3x}}\]
lololol

Answer 11

cool

Answer 12

jiji

Answer 13

thats some majorrrr chain ruleee bro