Question

this i dont know how to start... integrate ln(x^4)/x dx

Answer 1

The derivative of ln x is 1/x; you should be able to use U substitute to figure out the rest.

Answer 2

int by parts?

Answer 3

start with
\[4\int \frac{\ln(x)}{x}dx\]
the u - sub

Answer 4

ohh no dimple integration

Answer 5

Start by rewriting ln(x^4) as 4ln(x)
Then use ln(x)=u
(1/x)dx=du
Then you have:
\[4\int\limits udu=2u^2+C=2\ln^2(x)+C\]

Answer 6

what malevolence said

Answer 7

:D

Answer 8

My answer of course is assuming that x>0

Answer 9

:)