so why cant a limit exist at 2 numbers or more, only one?
sorry, i dk.
I don't know what you mean by this but. A limit only exists if the limit from the left and the limit from the right are equal.
hm ok, ill just take it as a rule, and understand it later then?
Limit exists if: \[\lim_{x \rightarrow n^+} f(x) =\lim_{x \rightarrow n^-} f(x) \]
paul do you mean why can't a function approach two different numbers or more? well there is left limit and there is a right limit we say the limit does not exist if we do not have left limit=right limit (or if there is an infinite discontinuity) when i say left limit it means what the function is approaching to the left of some number when i say right limit it means what the function is approaching to the right of some number
Actually, if the function diverges then you can say that the limit is infinity. Although infinity is not a number it is used to describe a limit.
thanks myininaya, rephrasing it that way makes it sound more obvious (plus i didn't even understand what i was asking/understand limits really) so thanks Alchemista, if i were to put that though, in an exam would i be able to say that it exists at infinity or -inf. ? or would i have to say it approaches infinity (or both +ve and -ve, depending on logarithmic, or exponential) and then proceed to say therefore it doesn't exist by definition of infinity which is an imaginary number.?
I think you are confusing the limit and "limit at". For some function f(x) the limit at some value a is the limit of f(x) as x approaches a \[\lim_{x \to a}f(x)\]
My point was if the function diverges to positive infinity or negative infinity from both sides at some point the limit is indeed infinity (either positive or negative)
oh i get that, im just trying to (now) find out the 'exam answer' if i were to get a quesiton that i would have to answer with infinity.
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