Question

integrate 1/x^2 -2x + 2 dx

Answer 1

what to do in the bottom?

Answer 2

completing the square?

Answer 3

I would start by completing the square to see if it is an arctan form before doing something like partial fractions.
\[\frac{1}{x^2-2x+2}=\frac{1}{x^2-2x+1-1+2}=\frac{1}{(x-1)^2+1}\]
\[\int\limits \frac{dx}{(x-1)^2+1}=\arctan(x-1)+C\]

Answer 4

oh cool.. i was not sure... :)

Answer 5

No problem :P