Question

solve sqr rt 3y+2=8

Answer 1

3y+2 is inside the square rte symbol

Answer 2

begin by squaring both sides

Answer 3

That way you get rid of the square root

Answer 4

\[(\sqrt{3y+2})^2=8^2\]\[3y+2=64\]\[3y=64-2\]\[y=\frac{62}{3}\]