Question

s=p/3+7q solve for p need help to solve

Answer 1

Start by substracting 7q from both sides of the equation

Answer 2

7q - s =7q- 7q+p/3
7q -s = p/3
7q-s/7=p/3
q-s=p/3 *p/p
q-s=3

Answer 3

s = p/3 + 7q
s - 7q = p/3 +7q - 7q <--- substracting 7q from both sides
s - 7q = p/3 <--- so we get this
3*( s - 7q) = (p/3) * 3 <--- now we multiply both sides by 3
3s - 21q = p <--- so we get this after the multiplication by 3
p = 3s - 21q <--- we are solving for "p" , so we write the equation this way

Answer 4

why did you multiple both sides by 3? let me guess so we could get rid of the p?

Answer 5

We had this equation:
s - 7q = p/3
and our goal was to solve for "p" .
In order to isolate the "p" out of the "p/3" we had to multiply "p/3" by 3 .
In order for the equation to remain valid, we must multiple everything on the other side of the equation by 3 as well.

So - we multiplied both sides of the equation by 3:

( s - 7q ) * 3 = (p/3) * 3

And that's how we got:

3s - 21q = p

which is the same as:

p = 3s - 21q

And we have solved for "p" as we were required to -
now we know what "p" is equal to, in terms of the other variables "s" and "q".

Answer 6

I understand how to do it know. Thanks

Answer 7

welcome!