solve

Question

solve

anonymous · Answer

solve what?

anonymous · Answer

attachment

anonymous · Answer

this

anonymous · Answer

You still haven't solved these XD... At least attempt them on your own.  If you at least try and come up with an answer, I will explain how to do them.  If you don't try, you will never learn :S.

anonymous · Answer

i agree. just a hint. try to get rid of radicals by squaring both sides of the equation

anonymous · Answer

i have done so you never responded to my answers

anonymous · Answer

It never told me you responded, my bad, can you post your old attempts/questions?

anonymous · Answer

where did my other post go?

anonymous · Answer

i think the last one would be 0

anonymous · Answer

Nope.  Plug 0 in for m, and you get 
-1=0
this isn't true.  To solve the last one....
$$4\sqrt(m-1)-\sqrt(15m)-1=0$$$$16(m-1)-15m-1=0$$$$m-2=0$$$$m=2$$
Hopefully the steps are self explanatory.  Square both sides, simplify.

anonymous · Answer

i found my first answer i came up with 15

anonymous · Answer

Nope :S.  Plugging in 15 gives
sqrt(202)=20.  
This isn't true.  To solve the first one..
$$\sqrt(9x+67)=5+x$$$$9x+67=x^2+10x+25$$$$x^2+x-42=0$$ Quadratic equation to get your answer, plug into original equation to verify that both solutions work.

anonymous · Answer

no m=15 not that problem