Question

e^2x

Answer 1

i mean find the point of intersection of y=e^2x and y =e^X+2

Answer 2

\[e^{2x}=e^x+2\]?

Answer 3

Yes satellite , but i don't know how to solve from there onwards.

Answer 4

oh ok

Answer 5

\[e^{2x}-x^x-2=0\]

Answer 6

now factor as in
\[z^2-z-2=0\] to get
\[(z+1)(z-2)=0\]

Answer 7

so you get
\[z=-1,z=2\]
\[e^x=-1,e^x=2\]
and of course
\[e^x=-1\] is not possible so
\[e^x=0\]
\[x=\ln(2)\]

Answer 8

oh i seeee thank you math whiz

Answer 9

where did you get e^x = 0 from and how does that become x =ln(2)

Answer 10

well the
\[e^x=0\] is a typo it should be
\[e^x-2=0\]
\[e^x=2\] and so
\[x=\ln(2)\]

Answer 11

oh ok , but how does e^x =2 become x = ln (2)

Answer 12

like how do you change exponentials to logarithms

Answer 13

that is equivalent logarithmic form

Answer 14

\[b^x=y\]
\[\log_b(y)=x\]

Answer 15

yes

Answer 16

they say the same thing. that is one simple explanation. other is that log and exp are inverse functions

Answer 17

does "yes" mean you agree? then it is clear right?
\[e^x=2\] same as
\[\log_e(2)=x\] i.e.
\]\ln(2)=x\]

Answer 18

\[\ln(2)=x\]

Answer 19

since
\[\ln\] means
\[\log_e\]

Answer 20

hahhaas yes means "yes i agree" thank you genius

Answer 21

=]

Answer 22

satelitte can you help me with this question also
find the are bounded by the y axis and the curves y=e^2x and y =e^X+2

Answer 23

*area