find the point of intersection of y=e^2x and y =e^X+2
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OpenStudy (anonymous):
you should have taken one equation as z or anything else
both can't be y
OpenStudy (anonymous):
huh? thats what the question says
OpenStudy (anonymous):
so i was thinking you can say that e^2x = e^X+2
but i don't now how to solve from there onwards
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
is capital x given? or is that normal x?
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OpenStudy (anonymous):
oh sorry its meant to be a normal x LOL
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
e^2x-e^x=2
e^x(e^x - 1) = 2
so either e^x = 2 or e^x = 3
OpenStudy (anonymous):
so x = log(2) ~ .7
OpenStudy (anonymous):
or x = log(3) ~ .47
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OpenStudy (anonymous):
what??
OpenStudy (anonymous):
no no my dear this is not right.
OpenStudy (anonymous):
well i dont know how is the log(3) coming here
OpenStudy (anonymous):
thank you mridul1 anyways!
OpenStudy (anonymous):
@vertus i answered in previous post
@mridul1 if you have
\[x(x-1)=2\] you cannot conclude that
\[x=2\] or
\[x=3\] or anything for that matter. you have to solve the quadratic
\[x^2-x-2=0\]
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OpenStudy (anonymous):
oh yes you're right my silly mistake
thanks for pointing it out