Question

Put the equation in the form ax^2+bx+c=0.
9-5x^2=(x+2)^2-4

Answer 1

but what part of 6x^2-5 would be the c part?

Answer 2

\[9-5x^2=\]\[(x+2)^2-4\]
(x+2)^2=\[x ^{2}+4x+4\]
\[9-5x ^{2}=x ^{2}+4x+4-4\]
\[6x ^{2}+4x-9\]
a=6,b=4,c=-9

Answer 3

i think this may not be right

Answer 4

Nick's answer is correct

Answer 5

thanks joe

Answer 6

oh yes. it just came through. only saw the first one. yes nick is right

Answer 7

yes yes yes.........nick's ans is crt.........sry..........

Answer 8

plz reward a medal if its correct.:)