if there is 1176 handshakes ..then how many members are present?

Question

saifoo.khan · Answer

1176/2

anonymous · Answer

That is only true if every one only handshakes one person...

anonymous · Answer

Yeah, I'd say the question is incomplete

saifoo.khan · Answer

Yeah!

anonymous · Answer

nope, lets use the formula for a Sum of numbers

Sum= n(n+1)/2 = 1076
and solve for n

$$n ^{2}+n -2352 = 0$$

the two possible values of x are (using the quadratic equation formula=

x = 48 & x= - 49

And since there cannot be negative amount of people. There are 48 people

anonymous · Answer

basically here, let us put all the people in a line and the last one will shake hands with everyone and then will leave the room... ok?

the following person will shake all but the last one (n-1) and so on until there is only one person, which will not shake anyones hand, as he has already done it with every one.

This a basic sum
$${\sum_{0}^{x}} = {n (n+1) \over 2}$$