Please help? Simplify 3 ---- x+3 --------- 1 3 --- + --- x+3 x
In that last question you posted, I submitted a more simplifed solution
It wouldn't be different for this problem?
This problem requires a bit of work...
\[\frac {3} {x+3} \over \frac {1} {x+3} + \frac {3} {x} \]
\[{ \frac {3} {x+3} \over \frac {1} {x+3} + \frac {3} {x} } = \frac {3} {x+3} \div \frac {1} {x+3} + \frac {3} {x} \]
The common denominator is (x+3)x
So multiply each fraction by whatever is missing:
\[\frac {3} {x+3} \over \frac {1} {x+3} + \frac {3} {x}\] multiply top and bottom by \[x(x+3)\] \[\frac {3} {x+3} \times x(x+3)\over (\frac {1} {x+3} + \frac {3} {x})\times x(x+3)\] \[=\frac{3x}{x+3(x+3)}\]
for a grand total of \[\frac{3x}{4x+9}\] unless i screwed up the algebra
I have a question on syntax. In the editor, how do you format the fraction so that it is vertical as opposed to horizontal?
3x/4x+3 or 3x/4x+9?
\[{{ \frac {3} {x+3} \over \frac {1} {x+3} + \frac {3} {x} } = \frac {3} {x+3} \div \frac {1} {x+3} + \frac {3} {x} } = \ \frac {3x} {x^2 + 3x} \div \frac {x} {x^2+3x} + \frac {3x+9} {x^2 +3x} \]
Hero, I think you are missing a couple important parentheses.
Satellite, you have to teach me how you're able to post multiple lines on the same post
i will stick with my answer but check it again
you mean like \[\frac{a}{b}\] \[\frac{c}{d}\]
Yeah, that...
i can show you but not here because it will format. i will show you in chAT
Well yes. A complex fraction.
\[{{ \frac {3} {x+3} \over \frac {1} {x+3} + \frac {3} {x} } =\frac {3} {x+3} \div (\frac {1} {x+3} + \frac {3} {x} })\]
i still get \[\frac{3x}{4x+9}\]
Yeah, satellite has it
ty i was beginning to worry
I keep forgetting to multply top and bottom by the lcd
Yeah I went over it and I think I go with satellite's answer. Thanks guys!
If you finish it supah fart, you will get the same answer
Satellites way is most simplest because he begins by multiplying top and bottom by the lcd
mathsux, I would have gotten there....just would've took a bit longer...I haven't figured out how to post multiple lines yet
I understand. Thank you hero :)
Join our real-time social learning platform and learn together with your friends!