Question

simplify and reduce to lowest terms. (y^(2)-6y)/(y^(2)+7y+12) x (y^(3)-7y^(2)+6y)/(y^(2)+9y+18) and show step how you got the answer please thank you

Answer 1

you gotta be kidding

Answer 2

first lets write the numerator it is
\[(y^2-6y)(y^3-7y^2+6y)\]

Answer 3

lest see how we can factor this
\[y(y-6)y(y^2-7y+6)\]
\[y^2(y-6)(y-1)(y-6)\]
that is the numerator

Answer 4

denominator is
\[(y^2+7y+12)(y^2+9y+18)\]

Answer 5

and again we factor it
\[(y+4)(y+3)(y+3)(y+6)\]

Answer 6

still with me?

Answer 7

now i am a little confused, because both numerator and denominator factor completely but i see no common factors top and bottom do you?

Answer 8

so nothing cancels and you just get what you get
\[\frac{y^2(y-6)^2(y-1)}{(y+3)^2(y+4)(y+6)}\]

Answer 9

okay

Answer 10

in real life very little cancels but these problems are usually cooked up so that there is lots of canceling . that is why i was a little confused

Answer 11

so what the answer with the step

Answer 12

i forgot to said you had to do reciprocal

Answer 13

it suppose to be y^2-6y/y^2+7y+12x y^2+9y+18/y^3-7y^2+6y