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1 6t + 62s = --- (3t 42s), for t 2 I have done some like this, but this one is confusing me. I want to actually see HOW to do it, not just the answer.
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\[6y+62s=\frac{1}{2}(3t+42s)\]?
Yes, but the 6y is actually 6t.
yes of course. i was just wondering about the plus sign
wanna get rid of the fraction first? multiply by 2 to get \[12t+124s=3t+42s\]
\[12t-3t=42x=124x\] \[11t=-81s\] \[t=\frac{-81s}{11}\] check my algebra
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yikes what a bunch of typos let me try again
9t = 166 t = 166/9
\[12t+124s=3t+42s\] \[12t-3t=42s-124s\] \[11t=-82s\] \[t=\frac{-82s}{11}\]
lol i followed the typos lol...
btw its 9t not 11 t
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yeah i suppose it is.
Ok thanks guys :)
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