Question

solve

Answer 1

I don't know if you're allowed to do this; I 'm not too experienced w/ radicals... but I squared the whole equation, making it 25(x-1) -24x=0, which eventually solves to x=26. Do you know if that's a legal math move?

Answer 2

First one:
\[5\sqrt{x-1}-\sqrt{24x-1}=0\]
It would be nice if we could just square this to get rid of the square roots, but first we need to rearrange it.
\[5\sqrt{x-1}=\sqrt{24x-1}\]
Square both sides.

\[5^2(\sqrt{x-1})^2=(\sqrt{24x-1})^2\]\[25(x-1)=24x-1\]Distribute the 25 to both the x and the -1.
\[25x-25=24x-1\]Add 25 to both sides.
\[25x=24x+24\]Subtract 24x from both sides.
\[x=24\]
Check x=24.
\[5\sqrt{24-1}-\sqrt{24(24)-1}=0\]

Answer 3

okay, missed the rearranging 1st step.
tnx 4 the answe- steps

Answer 4

answer steps

Answer 5

No worries :)

Answer 6

Thanks!

Answer 7

what would i do for the second one

Answer 8

could you square both sides again?

Answer 9

9x+55= (x+5)(x+5)

Answer 10

Yeppers.

Answer 11

9x+55= x^2+10x+25

Answer 12

You'll definitely need to check the solution you get for this one - it might have an extraneous solution.

Answer 13

oh dear

Answer 14

x^2+x-30=0

Answer 15

(x+6) (x-5)

Answer 16

x=-6, x=5

Answer 17

But it can't be the -6, because that would lead to an imaginary number- square root of a negative number, right?

Answer 18

Exactly.

Answer 19

Yay! Radicals, consider yourselves conquered

Answer 20

:)

Answer 21

as in the mathematical term, not the political affiliation

Answer 22

Panther, clear as mud?

Answer 23

yeah clearer than before

Answer 24

Okay, good :). Any questions about it?

Answer 25

thank the wizard :)

Answer 26

And the jabberwocky

Answer 27

lol