Question

can anyone show me how to solve the remaining questions please

Answer 1

@nancy
u have made a slight mistake...
once u put it in exponential form, you have to remove the root sign

\[\sqrt[4]{xy ^{3}z} = (xy ^{3}z)^{1/4} = x ^{1/4}y ^{3/4}z ^{1/4}\]

Answer 2

\[\sqrt[7]{x ^{-35}} = (x ^{-35})^{1/7} = x ^{-35/7} = x ^{-5} = 1/x ^{5}\]

Answer 3

but my answer is correct?

Answer 4

Yes ans is correct by method is wrong...☺
if u have \[(\sqrt{4})^{1/2} = (4^{1/2})^{1/2} = 4^{1/2*1/2} = 4^{1/4}\]

Answer 5

*but method is wrong

Answer 6

yes, ty I'm not good type

Answer 7

\[\sqrt{12}*\sqrt{375} = \sqrt{12*375} = \sqrt{2*2*3*3*5*5*5}\]
further this is equal to
\[2*3*5*\sqrt{5} = 30\sqrt{5}\]

Answer 8

@Nancy
no problem...
it was a minor error but can cost marks in a test.....

Answer 9

\[\sqrt{11} (\sqrt{2} - \sqrt{6}) = \sqrt{11}*\sqrt{2} - \sqrt{11}*\sqrt{6}\]
\[\sqrt{11*2} - \sqrt{11*6} = \sqrt{22} - \sqrt{66} = \sqrt{1*22} - \sqrt{3*22}\]
\[\sqrt{1}*\sqrt{22} - \sqrt{3}*\sqrt{22} = \sqrt{22}(\sqrt{1} - \sqrt{3})\]

Answer 10

is this the exact answer seems awful long?

Answer 11

in a shorter method we can do.....\[\sqrt{11} (\sqrt{2} - \sqrt{6}) = \sqrt{11}(\sqrt{2} - \sqrt{2*3}) \]
\[\sqrt{11}(\sqrt{2}-\sqrt{2}*\sqrt{3}) = \sqrt{11}*\sqrt{2}(1 - \sqrt{3})\]
\[\sqrt{22}(1-\sqrt{3})\]

Answer 12

Is it????\[\sqrt{7a} + \sqrt[3]{175a ^{3}}\]

Answer 13

???????

Answer 14

i am just trying to figure it all out

Answer 15

anything unclear????

Answer 16

is the last question as I have typed it??

Answer 17

the 3 is not in the square root sign

Answer 18

\[\sqrt{7a}+3\sqrt{175a ^{3}}\]

Answer 19

ok......

Answer 20

\[\sqrt{7a} + 3\sqrt{175a ^{3}} = \sqrt{7a} + 3\sqrt{5*5*7*a*a ^{2}}\]
\[\sqrt{7a} + 3*5*a \sqrt{7a} = \sqrt{7a} + 15a \sqrt{7a} = (1 + 15a)\sqrt{7a}\]

Answer 21

I hope all r done and clear......??☺

Answer 22

i think so