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Mathematics 13 Online
OpenStudy (anonymous):

find the derivative of the function y=xsin(2/x)

OpenStudy (anonymous):

can you show steps by steps please thanks

OpenStudy (anonymous):

dy/dx = sin2/x - 2* xcos(2/x) *1/x^2

OpenStudy (lalaly):

you differentiate x first and leave sin (2/x) the same + yu leave x and differentiate sin(2/x) and u get what ishaan got

OpenStudy (anonymous):

so how do i compute that..is that all i have to do?

OpenStudy (lalaly):

yess whenever u hav to differentiate two functions multiplied by each other yu differentiate the first one and write down the second one like itis then u differentiate the second and leav thefirstas it is,, and add them first u differentiate x which is 1 so u get sin(2/x) then yu differentiate only sin (2/x) and leave x u get x cos(2/x) * -2/x^2 and u add both sin(2/x) + x cos(2/x) * -2/x^2

OpenStudy (anonymous):

so thats the answer?

OpenStudy (lalaly):

yup

OpenStudy (lalaly):

u can simplify it yu get sin (2/x) - 2/x cos(2/x)

OpenStudy (anonymous):

ok..its just hard but ill practice.. thanks

OpenStudy (lalaly):

http://www.analyzemath.com/calculus/Differentiation/rules.html this could help, what i did is calld the product rule...

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