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Find the linearization of f(x) = x^3 + x at a = 2, and then use it to estimate f(2.2).
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take derivative of x^3+x
3x^2+1?
good. L(x)=f(x)+f'(x)dx f(x)=x^3+x f'(x)=3x^2+1
evaluate at 2
37?
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I think that's wrong :/ Ughh. Im so dumb
f'(2)=4 f(2)=2^3+2=10 dx=0.2 because we want to estimate 0.2( 2.2-2) f(2.2)=10+4(0.2)
then we add them?
10+4(0.2)=10.8
Its telling me the answer has to be between 12 and 14 :?
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f'(2)=13 (arithmethic error above) f(2)=2^3+13(.2)=10 dx=0.2 because we want to estimate 0.2( 2.2-2) f(2.2)=10+13(0.2)=12.6
what went wrong though? I cant find the error..
and thanks :) that answer is correct but what was wrong in our old answer?
plugging in 2 into 3x^2+1, I got 4 instead of correct answer of 13; silly arithmetic error
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