Question

Are there any holes or asymptotes in the graph of
f(x)= x^2-x-6
--------
x^2-2x-3

Answer 1

horizontal asympotes are the easier and require no math
they horizontal asymptote is y=1/1=1

Answer 2

easiest*

Answer 3

f(x)=(x-3)(x+2)
---------
(x-3)(x+1)

since the x-3 cancels this implies there is a hole at x-3=0 or x=3

Answer 4

\[{x^2-x-6 \over x^2-2x-3}={(x-3)(x+2) \over (x-3)(x+1)}={x+2 \over x+1}\]. So yeah there are asymptotes, one of them is the vertical asymptote at \(x=-1\).

Answer 5

and there is a veritcal asymptote at x+1=0 or x=-1

Answer 6

anwar!

Answer 7

Hey! :D

Answer 8

:)

Answer 9

How have you been?

Answer 10

i think i need some pills that calm me down
lol
how about you?

Answer 11

Take some :P.. I am alright!!

Answer 12

lol