how to solve dy/dt=1/2(sinx+cosx) differential equation?

Question

anonymous · Answer

aany one please reply me?

anonymous · Answer

dy/dt with respect to x??

anonymous · Answer

yes.

anonymous · Answer

u can' solve it. Not when it's dy/dt and with respect to x

anonymous · Answer

can you please help me how to solve with respective to dt.?

anonymous · Answer

Integral please help me...

anonymous · Answer

kramen the question should be:
dy/dt=1/2(sint+cost)

anonymous · Answer

okay. then which method is easy to solve the problem?

anonymous · Answer

Integral help me..

anonymous · Answer

Just integrate the whole thing that's all use:
wolframalpha.com

anonymous · Answer

its a separable equation:
$$\frac{dy}{dt}= \frac{1}{2}(sint+cost)$$
$$dy=\frac{1}{2}(sint+cost)dt$$
integrate both sides:
$$\int\limits dy= \frac{1}{2} \int\limits (sint +cost)dt$$
$$\int\limits dy= \frac{1}{2}[\int\limits sint dt+\int\limits costdt]$$
$$y=\frac{1}{2}(sint-cost)+C$$

anonymous · Answer

Integral help me..

anonymous · Answer

thank you nadeem and integral..! have a gr8 day..