i have five problems i have been trying to get help with since last night can anybody please look at them work them out and show me how they are done?
\[ \dfrac{(9\sqrt[3]{4} -6\sqrt[3]{4})} {\sqrt[3]{729}}\] Is this the first one?
i will post each one separately here ok
No, not all here, as separate questions, each with own thread. Is the above correct for the first one, we will do that one in here.
no i will correct it for you
This is the tex if you want to correct that instead.. \dfrac{(9\sqrt[3]{4} -6\sqrt[3]{4})} {\sqrt[3]{729}}
\[9\sqrt[3]{4}-6\sqrt[3]{4} subtract and simplify\]
Ok, let me look...
OK, I think your are letting the radicals get u confused, the same expression is in both terms so you can factor it out just as you would do with a normal equation: \[\sqrt[3]{4} (9-6) = 3 \sqrt[3]{4}\]
they look so much alike
The cube root of 4 can't be more simplified so you can just think of it as "x". 9x -6x = 3x
ok then what
Well, that 's the first question done, right? I saw you posted something else but the format is docx, I can't read it.
i will post the next one sec ty for your help i didnt mean to seem testy
Is the next question cube root of 729?
yes
Might as well do that one, it's 9. Do you have a calculator?
yes i do but im not sure how to do them on it
Ok, do you have a little symbol on your calculator looks like \[x^y\]
It's above X on mine...
next to another one looks like\[x^{\frac{1}{y}}\]
It's really easy once u know....
im sure i will need to post the next couple they are pretty large
Is number 3 (3 root 3 - 9 root 5)*(2 root 3 + 6 root 5)?
OK, don't know where u have gone, if it is like above, answer is -252. Now u should post the other questions 1 by 1.
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