Question

simplify: 2x - 1
---- ----
x^2-9 x-3

a) 2x-1
------
x^2-9

b) 2x-1
------
x+3

c) 2x-1
------
x-3

d) 1
----
x+3

e) 1
----
x-3

Answer 1

The answer is d)

Answer 2

thanks

Answer 3

2x/(x-3)(x+3) - 1/x-3
x-3/(x-3)(x+3)
1/x+3

Answer 4

\[\frac{2x}{x^2-9}-\frac{1}{x-3}\]


\[\frac{2x}{(x-3)(x+3)}-\frac{1}{x-3}\]


\[\frac{2x}{(x-3)(x+3)}-\left(\frac{1}{x-3}\right)\left(\frac{x+3}{x+3}\right)\]


\[\frac{2x}{(x-3)(x+3)}-\frac{1(x+3)}{(x-3)(x+3)}\]


\[\frac{2x}{(x-3)(x+3)}-\frac{x+3}{(x-3)(x+3)}\]


\[\frac{2x-(x+3)}{(x-3)(x+3)}\]


\[\frac{2x-x-3}{(x-3)(x+3)}\]


\[\frac{x-3}{(x-3)(x+3)}\]


\[\frac{1}{x+3}\]


So \[\frac{2x}{x^2-9}-\frac{1}{x-3}=\frac{1}{x+3}\]