Question

A solid cylinder of mass 10 kg is pivoted about a frictionless axis thought the center O. A rope wrapped around the outer radius R1 = 1.0m, exerts a force F1 = 5.0 N to the right. A second rope wrapped around another section of radius R2 = 0.50 m exerts a force F2 = 6.0 N downward. What is the angular acceleration of the disk?

Answer 1

\[\alpha=\Sigma \tau/\Sigma I\]\[\tau _{1}=F _{1}R _{1}\]\[\tau _{2}=F _{2}R _{2}\]\[I=1/2MR^{2}\]for each section of the cylinder

Answer 2

one of the torques may be negative if the rope is wrapped in the opposite direction of the other

Answer 3

You should note that this is probably not solvable with the info here.... the moment of inertia of the cylinder depends in how the mass is distributed around the rotation axis, and we are not really given that info: how much of teh mass goes with each section of the cylinder???

Answer 4

This is all the information that my online instructor gave me, though, so I'm just as confused. :/. I thank-you for your help though.