Question

8i/-1+3i=?

Answer 1

- 5 i

Answer 2

is it

$$\frac{8i}{-1}+3i$$

or $$\frac{8i}{-1+3i}$$

Answer 3

the second one

Answer 4

then the answer is

$$\frac{12-4i}{5}$$

Answer 5

but I need you solve every step

Answer 6

$$\frac{8i}{-1+3i}=\frac{8i}{-1+3i}\frac{-1-3i}{-1-3i}$$

$$=\frac{8i(-1-3i)}{(-1+3i)(-1-3i)}$$


$$=\frac{-8i+24}{(1+9)}$$


$$=\frac{-8i+24}{10}=\frac{-4i+12}{5}=\frac{12-4i}{5}$$

Answer 7

ok dear. Thanks

Answer 8

you great

Answer 9

hey you still there??

Answer 10

something not make sense to me

Answer 11

what

Answer 12

ok 8i(-1-3i)/(-1-3i)((-1-3i) can't be 8i+24/ 1+9 because 8i(-1-3i)= -8i-24i^2

Answer 13

\[8i(-1-3i)=-8i-24i^2=-8i-24(-1)=-8i+24\]

Answer 14

ah ok

Answer 15

thankss alot

Answer 16

no problem