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Mathematics 21 Online
OpenStudy (anonymous):

Evaluate the limit

OpenStudy (anonymous):

\[\lim_{x \rightarrow \infty}(e^x-1-5x)/x^2\]

OpenStudy (anonymous):

infinity

OpenStudy (anonymous):

you got \[e^x\] in the numerator which grows way way faster than \[x^2\] in fact \[e^x\] grows faster than any polynomial

OpenStudy (anonymous):

is this by inspection? or is there work to be shown?

OpenStudy (anonymous):

i just need the answer...I got 0.5 but they said its wrong

OpenStudy (anonymous):

no work needs to be shown

OpenStudy (zarkon):

satellite73 gave you the answer

OpenStudy (zarkon):

$$\infty$$

OpenStudy (anonymous):

how did you get that sir

OpenStudy (anonymous):

infinity isnt correct

OpenStudy (anonymous):

sorry i wrote the problem wrong its e^5x

OpenStudy (zarkon):

it is

OpenStudy (anonymous):

are you there?

OpenStudy (zarkon):

the answer to the problem you posted is infinity

OpenStudy (anonymous):

yeah i wrote it wrong...its (e^5x-1-5x)/x^2

OpenStudy (anonymous):

do we need to redo this? if it is the limit as x goes to infinity the answer is infinity with just common sense and no work needed

OpenStudy (anonymous):

still infinity

OpenStudy (anonymous):

it is the x going to 0...sorry I screwed this question all the way up

OpenStudy (anonymous):

so is the answer 0

OpenStudy (zarkon):

25/2

OpenStudy (anonymous):

ok please explain how u got it

OpenStudy (zarkon):

L'Hopitals rule

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