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OpenStudy (anonymous):
Evaluate the limit
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OpenStudy (anonymous):
\[\lim_{x \rightarrow \infty}(e^x-1-5x)/x^2\]
OpenStudy (anonymous):
infinity
OpenStudy (anonymous):
you got
\[e^x\] in the numerator which grows way way faster than \[x^2\] in fact
\[e^x\] grows faster than any polynomial
OpenStudy (anonymous):
is this by inspection? or is there work to be shown?
OpenStudy (anonymous):
i just need the answer...I got 0.5 but they said its wrong
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OpenStudy (anonymous):
no work needs to be shown
OpenStudy (zarkon):
satellite73 gave you the answer
OpenStudy (zarkon):
$$\infty$$
OpenStudy (anonymous):
how did you get that sir
OpenStudy (anonymous):
infinity isnt correct
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OpenStudy (anonymous):
sorry i wrote the problem wrong its e^5x
OpenStudy (zarkon):
it is
OpenStudy (anonymous):
are you there?
OpenStudy (zarkon):
the answer to the problem you posted is infinity
OpenStudy (anonymous):
yeah i wrote it wrong...its (e^5x-1-5x)/x^2
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OpenStudy (anonymous):
do we need to redo this? if it is the limit as x goes to infinity the answer is infinity with just common sense and no work needed
OpenStudy (anonymous):
still infinity
OpenStudy (anonymous):
it is the x going to 0...sorry I screwed this question all the way up
OpenStudy (anonymous):
so is the answer 0
OpenStudy (zarkon):
25/2
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OpenStudy (anonymous):
ok please explain how u got it
OpenStudy (zarkon):
L'Hopitals rule
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