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Determine the sum of a geometric series whose first term is 12, whose common ratio is -1/4 and whose number of terms is infinite.
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i tried what u said last time but got a answer that was not on there wanted to make sure it was none of they above
the*
which one , the previous?
yeah i tried what u said on the last one
\[\frac{c}{1-r}\]
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is it 16?
\[\frac{12}{1+\frac{1}{4}}\]
i got 12.25? thst right?
but i did 12/1-(-1/4)
\[\frac{12}{\frac{5}{4}}\] \[12\times \frac{4}{5}=9.6\]
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oh yeah 1+ 1/4 is not 3/4
did i mess up?
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