Calc integral question:

Question

anonymous · Answer

attachment

anonymous · Answer

I'll try it, hold on...

anonymous · Answer

Use a u sub for the part in parens.

anonymous · Answer

set x^3+9=U

making du=3x^2 dx

plug in necessary substitutions

and your integral becomes   $$\int\limits_{?}^{?}(x^2/3x^2)u^9 du$$ the x^2 will cancel and you integral will now become

$$\int\limits_{?}^{?}1/3 u^9 du$$ 

now take integral interms of u, then plug back in the x^3 +9 for u after the integral is taken

anonymous · Answer

I got (x^3+9)/30 +c I'll upload my notes, let me know if you have any questions

anonymous · Answer

http://www.evernote.com/shard/s103/sh/2371bccc-9cf8-47a1-8992-b6df6a8fd2c7/3f1374193f481d8f0593d7ead5d42b2e

anonymous · Answer

polpak how do you become a mod?

anonymous · Answer

I have no idea. They emailed me and asked. I said ok.

anonymous · Answer

lmao u serious?

anonymous · Answer

indeed

anonymous · Answer

Dave, that answer is incorrect unfortunately.  anyone have another answer?

anonymous · Answer

sorry should say (x^3+9)^10

anonymous · Answer

^answer divided by 30

anonymous · Answer

Nice.  Thanks, zaned55/Dave321, that is correct. :)