Question

x^3+x^-xy^2-y^2

Answer 1

This isn't even an equation - what are we to do with it?

Answer 2

x^3+x^2-xy^2-y^2
thats the equation the teacher gave us
help!

Answer 3

Are we supposed to reduce it...or what? That's like yelling a statement like: "I have hemorrhoids!" And expecting people to answer it. In fact people will just stare at you...like a freak...and then walk along keeping a good distance from you.

Answer 4

factor it

Answer 5

please be polite and show me how to do this

Answer 6

Is that (x^3)+(x^2)-(xy^2)-(y^2)?

Answer 7

no thery are not like that,, the numbers suppost to be the exponent,

Answer 8

(x^3)+(x^2)-(x^2)-(y^2)? You have an xy^2 in there and it doesn't seem to fit. Can you please CAREFULLY write out the exact set of variables and numbers?

Answer 9

that is just the exact equation i wrote it down.

Answer 10

No...no it's not. You wrote: "x^3+x^-xy^2-y^2" rather than "(x^3)+(x^2)-(x^2)-(y^2)"

Give me a min.

Answer 11

sure

Answer 12

Hmm, that doesn't make sense - the +x^2 and the -x^2 cancel each other out. Check your damn problem. Pisses people off if you're too damn lazy to write it out correctly.

Answer 13

lool i swear to god thats how the freaken equation is written, dammn it,
the answer to the question is (x+1)(x+y)(x-y)

Answer 14

solve,=\[x ^{3}+x ^{2}-xy ^{2}-y ^{2}\]

Answer 15

\[(x^3+x^2)-(xy^2+y^2)\]\[x^2(x+1)-y^2(x+1)\]\[(x+1)(x^2-y^2)\]\[(x+1)(x+y)(x-y)\]

Answer 16

factor by group

Answer 17

\[3-x \div x ^{2}-3x\]

Answer 18

thanks nancy