Mathematics
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OpenStudy (anonymous):
9c^3+7c-(3c^3-12+c)
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OpenStudy (anonymous):
I want to double check something:
The 9c^3, is the ^3 only on the c, or is it on the entire 9c?
OpenStudy (anonymous):
Same question with the 3c^3
OpenStudy (anonymous):
its written just like that in he problem
OpenStudy (anonymous):
Okie dokie. So we can assume it's only connected on the c.
OpenStudy (anonymous):
First thing you can see is that we have no like terms that we can combine. So technically our PEMDAS is useless.
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OpenStudy (anonymous):
However, you can distribute the - to the stuff in the parentheses.
So what do we get?
Also, POLPAK!
OpenStudy (anonymous):
I find pemdas useless generally anyway.
OpenStudy (anonymous):
^ :O
How could you hate on the standard order of operations?
OpenStudy (anonymous):
Because I rarely use it. And it often confuses people.
OpenStudy (anonymous):
so all the signs change in the parenthesis
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OpenStudy (anonymous):
Yes, because you must distribute the -1 to each term.
OpenStudy (anonymous):
But if you don't use it, we get wrong answers! Someone might write 2+3^2 as 25 instead of 11!
OpenStudy (anonymous):
now combine like terms
OpenStudy (anonymous):
Correct. :D
OpenStudy (anonymous):
pemdas is a restriction on what you cannot do, not a procedure for what you should do.
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OpenStudy (anonymous):
9c^3+9 or -9
OpenStudy (anonymous):
9c^3 - 3c^3
OpenStudy (anonymous):
how did you get that
OpenStudy (anonymous):
9c^3 + 7c - (3c^3 -12 + c)
^this ^minus ^this
OpenStudy (anonymous):
You're combining your like terms right?
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
So you have 9 c^3's and you are subtracting 3 of them.
OpenStudy (anonymous):
9c^3 - 3c^3 = 6c^3 is what we'll have left as far as the c^3's go.
OpenStudy (anonymous):
where did the 12 go
OpenStudy (anonymous):
Then we look at the c's We start with 7, how many are being subtracted?
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OpenStudy (anonymous):
no-where. We haven't got to the 'ones' terms yet
OpenStudy (anonymous):
3c^3-6c+12
OpenStudy (anonymous):
no.
OpenStudy (anonymous):
ugh
OpenStudy (anonymous):
9c^3 - 3c^3 = 6c^3
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OpenStudy (anonymous):
So you have six c^3's not three of them.
OpenStudy (anonymous):
got a second? I can show easier on a whiteboard.
OpenStudy (anonymous):
right 6c^3-6c+12
OpenStudy (anonymous):
closer.
OpenStudy (anonymous):
i was putting wrong numbers
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OpenStudy (anonymous):
Why is the middle term negative? How many c's did you start with, and how many did you subtract?
OpenStudy (anonymous):
7c - c = 6c not -6c
OpenStudy (anonymous):
its suoppose to be + beccause its 7-6
OpenStudy (anonymous):
right
OpenStudy (anonymous):
6c^3+6c+12
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OpenStudy (anonymous):
yep
OpenStudy (anonymous):
You can also factor a 6 if you care, but it's not important
OpenStudy (anonymous):
i was jus about to ask that
OpenStudy (anonymous):
it cant go any lower can it
OpenStudy (anonymous):
nope. you can factor it, but it won't cancel or anything.
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OpenStudy (anonymous):
Yay.
OpenStudy (anonymous):
6(c^3 + c+ 3)