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Mathematics 14 Online
OpenStudy (anonymous):

9c^3+7c-(3c^3-12+c)

OpenStudy (anonymous):

I want to double check something: The 9c^3, is the ^3 only on the c, or is it on the entire 9c?

OpenStudy (anonymous):

Same question with the 3c^3

OpenStudy (anonymous):

its written just like that in he problem

OpenStudy (anonymous):

Okie dokie. So we can assume it's only connected on the c.

OpenStudy (anonymous):

First thing you can see is that we have no like terms that we can combine. So technically our PEMDAS is useless.

OpenStudy (anonymous):

However, you can distribute the - to the stuff in the parentheses. So what do we get? Also, POLPAK!

OpenStudy (anonymous):

I find pemdas useless generally anyway.

OpenStudy (anonymous):

^ :O How could you hate on the standard order of operations?

OpenStudy (anonymous):

Because I rarely use it. And it often confuses people.

OpenStudy (anonymous):

so all the signs change in the parenthesis

OpenStudy (anonymous):

Yes, because you must distribute the -1 to each term.

OpenStudy (anonymous):

But if you don't use it, we get wrong answers! Someone might write 2+3^2 as 25 instead of 11!

OpenStudy (anonymous):

now combine like terms

OpenStudy (anonymous):

Correct. :D

OpenStudy (anonymous):

pemdas is a restriction on what you cannot do, not a procedure for what you should do.

OpenStudy (anonymous):

9c^3+9 or -9

OpenStudy (anonymous):

9c^3 - 3c^3

OpenStudy (anonymous):

how did you get that

OpenStudy (anonymous):

9c^3 + 7c - (3c^3 -12 + c) ^this ^minus ^this

OpenStudy (anonymous):

You're combining your like terms right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

So you have 9 c^3's and you are subtracting 3 of them.

OpenStudy (anonymous):

9c^3 - 3c^3 = 6c^3 is what we'll have left as far as the c^3's go.

OpenStudy (anonymous):

where did the 12 go

OpenStudy (anonymous):

Then we look at the c's We start with 7, how many are being subtracted?

OpenStudy (anonymous):

no-where. We haven't got to the 'ones' terms yet

OpenStudy (anonymous):

3c^3-6c+12

OpenStudy (anonymous):

no.

OpenStudy (anonymous):

ugh

OpenStudy (anonymous):

9c^3 - 3c^3 = 6c^3

OpenStudy (anonymous):

So you have six c^3's not three of them.

OpenStudy (anonymous):

got a second? I can show easier on a whiteboard.

OpenStudy (anonymous):

right 6c^3-6c+12

OpenStudy (anonymous):

closer.

OpenStudy (anonymous):

i was putting wrong numbers

OpenStudy (anonymous):

Why is the middle term negative? How many c's did you start with, and how many did you subtract?

OpenStudy (anonymous):

7c - c = 6c not -6c

OpenStudy (anonymous):

its suoppose to be + beccause its 7-6

OpenStudy (anonymous):

right

OpenStudy (anonymous):

6c^3+6c+12

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

You can also factor a 6 if you care, but it's not important

OpenStudy (anonymous):

i was jus about to ask that

OpenStudy (anonymous):

it cant go any lower can it

OpenStudy (anonymous):

nope. you can factor it, but it won't cancel or anything.

OpenStudy (anonymous):

Yay.

OpenStudy (anonymous):

6(c^3 + c+ 3)

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