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OpenStudy (anonymous):
If 6<|x-3|<7 and x<0 find the value of |x|
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OpenStudy (anonymous):
don't you hate these?
OpenStudy (anonymous):
a smidge.
OpenStudy (anonymous):
especially when you have to start proving things with them.
OpenStudy (anonymous):
haha that is the best part...NOT!
OpenStudy (anonymous):
-7<x-3<-6
-4<x<-3
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OpenStudy (anonymous):
oh it wants the abs value.....
3<|x|<4
OpenStudy (anonymous):
ok lets see.
\[6<|x-3|\] gives
\[6<x-3\] or
\[x-3<-6\] first ones says
\[3<x\] so we throw it out
second one says
\[x<-3\] so that is possible
OpenStudy (anonymous):
haha that is the best part...NOT!
OpenStudy (anonymous):
joemath is right !
OpenStudy (anonymous):
second one says
\[|x-3|<7\] means
\[-7<x-3<7\]
\[-4<x<10\]
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OpenStudy (anonymous):
so we know that
\[x<0\]
\[x<-3\]
\[x>-4\] making the interval
\[(-4,-3)\] unless my algebra is bad
OpenStudy (anonymous):
thats right.
OpenStudy (anonymous):
well not nearly as snappy as your way
OpenStudy (anonymous):
but more thorough . and definitely appreciated!
OpenStudy (anonymous):
guess thinking is better. since
\[x<0\] we know
\[|x-3|=3-x\]
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OpenStudy (anonymous):
so put
\[6<3-x<7\]
\[3<-x<4\]
\[-4>x>-3\] easy
OpenStudy (anonymous):
12?
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