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Mathematics 12 Online
OpenStudy (anonymous):

If 6<|x-3|<7 and x<0 find the value of |x|

OpenStudy (anonymous):

don't you hate these?

OpenStudy (anonymous):

a smidge.

OpenStudy (anonymous):

especially when you have to start proving things with them.

OpenStudy (anonymous):

haha that is the best part...NOT!

OpenStudy (anonymous):

-7<x-3<-6 -4<x<-3

OpenStudy (anonymous):

oh it wants the abs value..... 3<|x|<4

OpenStudy (anonymous):

ok lets see. \[6<|x-3|\] gives \[6<x-3\] or \[x-3<-6\] first ones says \[3<x\] so we throw it out second one says \[x<-3\] so that is possible

OpenStudy (anonymous):

haha that is the best part...NOT!

OpenStudy (anonymous):

joemath is right !

OpenStudy (anonymous):

second one says \[|x-3|<7\] means \[-7<x-3<7\] \[-4<x<10\]

OpenStudy (anonymous):

so we know that \[x<0\] \[x<-3\] \[x>-4\] making the interval \[(-4,-3)\] unless my algebra is bad

OpenStudy (anonymous):

thats right.

OpenStudy (anonymous):

well not nearly as snappy as your way

OpenStudy (anonymous):

but more thorough . and definitely appreciated!

OpenStudy (anonymous):

guess thinking is better. since \[x<0\] we know \[|x-3|=3-x\]

OpenStudy (anonymous):

so put \[6<3-x<7\] \[3<-x<4\] \[-4>x>-3\] easy

OpenStudy (anonymous):

12?

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