Evaluate the integralhttp://www.webassign.net/cgi-bin/symimage.cgi?expr=int_%28-2%29%5E%283%29%20%5C%28x%5E3-4%20x%5C%29%20dx

Question

anonymous · Answer

i got this to be -23/4 but thats not right please give me answer

anonymous · Answer

joemath will do it

anonymous · Answer

ok

anonymous · Answer

like how i volunteered you?

anonymous · Answer

i dont like calculus, you do it =/

anonymous · Answer

lol

anonymous · Answer

i dont think ive answered a single calculus question since ive been on this site >.<

anonymous · Answer

er, computational anyways.

anonymous · Answer

take the antiderivative using power rule backwards. 
plug in 3
plug in -2
subtract second number from first

anonymous · Answer

but whats the answer i know how to do it i jsut wanna see where i went wrong

anonymous · Answer

$$\int x^3dx=
\frac{x^4}{4}$$

anonymous · Answer

$$\int -4xdx=-x^2$$

anonymous · Answer

so get 
$$F(x)=\frac{x^4}{4}-2x^2$$

anonymous · Answer

thats what the answer is?

anonymous · Answer

$$F(3)=\frac{3^4}{4}-2\times 3^2=\frac{9}{4}$$

anonymous · Answer

$$F(-2)=\frac{(-2)^4}{4}-2\times (-2)^2=-4$$

anonymous · Answer

and finally 
$$
\frac{9}{4}-(-4)=\frac{9}{4}+4=\frac{25}{4}$$