Question

pOH of 0.015M Mg(OH)2

how is this calculated?

Answer 1

is the answer 1.52?

Answer 2

Im pretty sure but I could be wrong:

So Mg(OH)2 dissolves in water to form Mg ions and 2OH-
The concentration of OH- is then 2x the concentration of Mg(OH)2 (writing out the formula will help if you dont understand)
The concentration is then 0.030M
The pOH is defined as -log[OH]
So your pOH is equal to -log(0.030)
I dont have a calculator on hand but im sure you do! good luck

Answer 3

thank you!!