Question

find the center and the radius of the circle with this equation
x^2+y^2+4x+2y+3=0

Answer 1

\[x ^{2}+y ^{2}+4x+2y+3=0\]

Answer 2

the center is (-2,-1) yes?

Answer 3

U need to get this into the form

(x-a)^2 + (y-b)^2 = r^2

Answer 4

Yes.

Answer 5

so the radius is either sqrt2 or sqrt3\[\sqrt{2} or \sqrt{3}\]

Answer 6

Now just shuffle things around till u get an integer on the right and the radius is the positive square root.

Answer 7

is it the sqrt3?

Answer 8

I haven't done it, let me look..

Answer 9

I make it sqrt 2

Answer 10

Your (x+2)^2 gives you a -4 and your

(y+1)^2 gives you a -1 so

-4-1 +3 = -2 is 2 on the other side, take square root.