Question

y<1/2x+6, x+3y>+12 how do i graph those equations?

Answer 1

They are inequalities, not equations.

To graph them, start by graphing the equation (with a solid line if they are \(\le\) or \(\ge\) or a doted line if they are \(\gt or \lt\)). Then shade the area above or below that line if it's greater or less respectively.

Answer 2

is it two separate relations? or is it a system that you're trying to graph here?

Answer 3

its supposed to be an area bounded by those equations on a graph

Answer 4

right but how do i graph those two inequalities?

Answer 5

I just explained.

Answer 6

Graph them like they are equations. But use a dotted line.

Answer 7

oh so i would start at 6 and then use 1/2 as the slope?

Answer 8

Then shade the region above or below the line depending on if the y is greater or less than the expression.

Answer 9

Yes

Answer 10

If you are looking for a bounded region than it must be above one, AND below the other.

Answer 11

You have to solve the second one for y before you graph it.

Answer 12

i feel like what your explaining is very simple but i dont understand how to make those inequalities onto a graph

Answer 13

i feel like what your explaining is very simple but i dont understand how to make those inequalities onto a graph

Answer 14

sorry about being slow