Question

if i subtract x^2 from, x^2 do i get x? or just no variable?

Answer 1

anything-itself=0

Answer 2

If you subtract a from a you get?

Answer 3

u get zero

Answer 4

No matter what a is (a=x^2 for example)

Answer 5

okay, so i dont use the variable?

Answer 6

And anyway, remember what I told you before. If you are adding or subtracting the exponents will not change.

Answer 7

1x^2-1x^2=0*x^2

Answer 8

but 0 times anything is 0

Answer 9

but if you are dividing, you subtract exponents...thats what my problem is that i am working on

Answer 10

1*x^2-1*x^2=1*(x^2-x^2)=1*0=0
does this look better to you

Answer 11

\[x^2 - x^2\]\[=1x^2 - 1x^2\]\[=x^2( 1-1)\]\[=0x^2\]\[=0\]

Answer 12

so pretty polpak

Answer 13

i should had factor the the x^2 out instead
darn it

Answer 14

Please give the problem so we can understand what you mean lish. Are you subtracting x^2 from x^2 or are you dividing x^2 by x^2 ?

Answer 15

\[\frac{x^2}{x^2}=1\]

Answer 16

since \[1*x^2=x^2\]

Answer 17

\[\frac{a}{a} = 1,\ \forall a \ne 0\]

Answer 18

\[\frac{x^2}{x^2}=x^{2-2}=x^0=1\]

Answer 19

sorry: the problem is 35x^5-35x^4+21x^2 / -7x^2

Answer 20

\[\frac{35x^5-35x^4+21x^2}{-7x^2}?\]

Answer 21

hey polpak after ur done helping this student please check out my question, thank you :)

Answer 22

yes, thank you

Answer 23

well i think you meant to write what i write
i can read the way you right it but the i translated what you wrote is not what it should translate to
what you wrote should translate to
\[-35x^4+\frac{21x^2}{-7x^2}\]

Answer 24

i suck at making sentences lol

Answer 25

which is the correct translation?

Answer 26

\[35x ^{5}-35x^4+21x^2 \div -7x^2\]

Answer 27

\[-6x^{2}+35x^{5}-35x^{4}\]

Answer 28

that is what i got