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Mathematics 7 Online
OpenStudy (anonymous):

xyz/ xy+yz+xz how do you simplify this??

OpenStudy (anonymous):

I'm not sure what do you mean with "symplifying", I'll try to do my best: 1) \[(xyz / xy ) + yz + xz\] 2) \[z + yz + xz\] 3) \[z(y+x)\] The last is the final result :P

OpenStudy (anonymous):

i dont understand how you got the step 1

OpenStudy (anonymous):

Well, step 1 is the same as you wrote. In step 2 I divided the "xy" with "xy" which makes "1". That is step 2. And step 3 is factorization :P

OpenStudy (anonymous):

was this the original problem? \[\frac{xyz}{xy+yz+xz}\]

OpenStudy (anonymous):

the way you have it typed in the problem leads to it being interpreted in more than one way.

OpenStudy (anonymous):

I think so @joemath314159! so I didn't understand it correctly T_T

OpenStudy (anonymous):

yes joe math is correct

OpenStudy (anonymous):

it looks as simplified as i'd want it. The only thing i can think of is: \[xy = \frac{xyz}{z},yz = \frac{xyz}{x}, xz = \frac{xyz}{y}\] so the denominator of the fraction becomes: \[xy+yz+xz = \frac{xyz}{z}+\frac{xyz}{x}+\frac{xyz}{y} xyz(\frac{1}{z}+\frac{1}{x}+\frac{1}{y})\] Now your whole fraction looks like: \[\frac{xyz}{xyz(\frac{1}{z}+\frac{1}{x}+\frac{1}{y})} = \frac{1}{\frac{1}{z}+\frac{1}{x}+\frac{1}{y}}\] While that looks a little cleaner (less variables), i dont know...having fractions in the denominator of a fraction seems taboo lol

OpenStudy (anonymous):

oops, in my second equation line there should be an equal sign inbetween: \[\cdots \frac{xyz}{y} = xyz\cdots \]

OpenStudy (anonymous):

ok! that makes complete sense because the variables are supposed to appear as little as possible..thanks!!

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