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Mathematics 19 Online
OpenStudy (anonymous):

help,please!

OpenStudy (anonymous):

\[2^n=\sqrt{3^{n-2}}\]

OpenStudy (anonymous):

take ln of both sidez

OpenStudy (anonymous):

nln2=(1/2n-1)ln3

OpenStudy (anonymous):

n=(-ln3/(ln2-1/2ln3)

OpenStudy (anonymous):

square both sides 2^(2n)=3^(n-2) natural log of both sides ln(2^(2n))=ln(3^(n-2)) take the power down (2n)ln(2)=(n-2)(ln(3)

OpenStudy (anonymous):

(2n)ln(2)-n(ln(3)=-2ln(3) n(2ln(2)-ln(3))=-2ln(3) n(ln(4)-ln(3))=2ln(3) n(ln(4/3))=2ln(3) n=(2ln(3))/(ln(4/3))

OpenStudy (anonymous):

I can do any farther from her:\[(n)\log(2)=(\frac{n-2}{2})\log(3)\]

OpenStudy (anonymous):

yeah thats right

OpenStudy (anonymous):

\[(2n)\log(2)=(n)\log(3)-(2)\log(3)\]

OpenStudy (anonymous):

then combine the ones with variable n

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