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\[2^n=\sqrt{3^{n-2}}\]
take ln of both sidez
nln2=(1/2n-1)ln3
n=(-ln3/(ln2-1/2ln3)
square both sides 2^(2n)=3^(n-2) natural log of both sides ln(2^(2n))=ln(3^(n-2)) take the power down (2n)ln(2)=(n-2)(ln(3)
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(2n)ln(2)-n(ln(3)=-2ln(3) n(2ln(2)-ln(3))=-2ln(3) n(ln(4)-ln(3))=2ln(3) n(ln(4/3))=2ln(3) n=(2ln(3))/(ln(4/3))
I can do any farther from her:\[(n)\log(2)=(\frac{n-2}{2})\log(3)\]
yeah thats right
\[(2n)\log(2)=(n)\log(3)-(2)\log(3)\]
then combine the ones with variable n
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