Question

Write the slope-intercept equation for the line that passes through (14, -2) and is perpendicular to 7x – 10y = 18

y=-7/10x+9/5 is where i am stuck at?

Answer 1

okay coz its perpendicular then the slope of the other line is 10/7

Answer 2

so i need to y=mx+b

Answer 3

im confused

Answer 4

okay two lines if they are perpendicular, there slope if multiply together yu get -1

Answer 5

so coz the slope of the first equation was -7/10
then yu take the reciprocal of -7/10 and multiply by -1

Answer 6

y=(10/7)x+b

Answer 7

and then use the given point (14,-2) -2=20+b b=-22 y=(10/7)x-22

Answer 8

That slope might be (-10/7) for the newly found perpendicular line. Double check!

Answer 9

yes thats true..... i jst kept on working from where she got stuck

Answer 10

miss_texas are you still there?

Answer 11

yes i am getting a diff answer

Answer 12

y=10/7x+9/5

(y-y1)=m(x-x1)

(y+2)=10/7(x-14)

Answer 13

First express the given line in the slope intercept form y=mx+b.
Like this: 7x-10y=18 -10y=-7x+18 y=(-7/-10)x +18 or
y=7x/10+18 Slope is 7/10
For a line to be perpendicular to this line, its slope must be the negative reciprocal as jkip706 explained. Or the slope must be -10/7.

now you can plug one of the points in and create the equation for the new line.
the point P is (14,-2)
x=14, y=-2
-2=(-10/7)(14)+b
-2=-20+b
b=-2+20=18
thats all you need now write the equation: y=(-10/7)x+18

Answer 14

is that suppose to be my final answer

Answer 15

Yes, and where you got stuck was your treatment to the signs. If you had treated the signs correctly you would not come up with y=(-7/10)x+9/5 but would of gotten
y=(7/10)x-9/5

Answer 16

Did you find your error?