Can someone explain this real quick? Should be easy.. I'm just dumb lol (picture coming)
Still here? I'll teach ya.
Just let me know when you get here and I'll explain it.
That'd be awesome, thank you, I appreciate it
SORRY to intrude. Thought writing it out for you might help. Graph the following inequality on the number line\[(x-3)(x-7)\le0\]
x^2-10x+21?
Thank you Dr. Lambert, that helps by no having to refer back to the image each time to check
WAIIIITTTT...... I'm an idiot. Ignore everything I said.
lol ok
Ok... sorry. What we REALLY want to do (and we only skip the parentheses because there's already (factor)(factor) <= (zero) ) is find the zeroes of the function. Go ahead and tell me what they are.
And thank you dr. lambert! That saves time. :D
+,- 1,3,7,21?
Not really. You just need to find the two values of X that when plugged into a parenthesis will equal zero.
In other words, you want this: (0)(anythingelse) = 0 and (anythingelse)(0)=0 So which two values will lead to this?
Does that make sense?
3 and 7
Perfect.
Now, if we were to draw a parabola on a graph, what significance do 3 and 7 have for us?
x is greater than or equal to 3 but less than or equal to 7?
I meant if we drew it on a graph, what is the point of finding the "zeroes"? Do you know? Hint: because your x's result in zeros, this means that your points will be (3,0) and (7,0). What does this mean on a graph?
(hint: think intercepts)
Err.. I don't quite get what you're getting at
Well, tell me this: If we put those points on a graph, where would they be? The (3,0) and (7,0)?
On the x-axis.. right? At (3,0) and (7,0)
If we had y<=0, what portion of a graph would we color in?
in other words, which portion of a graph would have y values that are equal to or less than 0?
Everything positive?
Errr sorry sorry, negative
Kinda. Everything negative and.... what?
and equal to
Hint: y is less than or 'equal' to zero.
What I'm hinting at is that we want zero and everything below, right?
Also, if you meet me up here, it'll make more sense. http://www.scribblar.com/vrkg0wkx
Ok sure, thank you, I really appreciate this!
No probs! I'm just glad that you're actually participating instead of just asking for answers. :P
heh yeah.. when I try to help people with what I can, they just want answers too ;D
Good work! For anyone wanting to see what was done, just check out the room linked above.
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