f(x) = xe^3/x a) Use l'Hospital's Rule to determine the limit as x 0+. b)Use calculus to find the local minimum value. c)Find the interval where the function is concave up. d) Find the interval where the function is concave down.
Yay right up my alley, love calculus!
wait is it f(x) = x * e^(3/x)?
yes
okay so rewrite that as: f(x) = e^(3/x)/ (1/x)
according to l'hopitals the limit of that as it goes to 0, is: (e^(3x^-1))'/(x^-1)'
hold on.. actually can we go on twiddla?
As I showed u on twiddla the limit diverges.
Here's the picture..
what is diverges
Does not exist = goes to infinity, answer is inifinity techincally..
f(x) = xe^3/x 2) Use calc to find the local min: that simply means taking the derivative: f'(x) = x*e^(3/x) oh god I hate it when there's a variable in the power.. go back to that twiddla.. this will be messy.
that wasnt right for the limit
From the plus side? yes it was, and wolframalpha confirms it. Otherwise your question is wrong.
no it wasnt right
im putting it into my online homework it said its wrong
can't be true, check the question then. Look wolframalpha is always true.
okay can i see a screen of ur online hw?
Try undefined, undef, DNE, infinity, infinity symbol, etc..
f(x) = x*e^(3/x)
infinity was right
how do i do the others?
okay let's go back to twiddla..
u are confusing me!
try x = 3 or x = 0, im too bored to check which one is max and which one is min.
did we get it?
nope
what is that showing
The actual limits. It doesn't show you how to work them out.
yes but it doent show the minimum or concave up or down
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