Question

Algebra 2!
Quadratic equations that can be solved using the quadratic formula can also be solved by factoring.
A. Always
B. Never
C. Sometimes

Answer 1

C

Answer 2

C

Answer 3

Lol.
wrong PAste

Answer 4

i know the answer they are looking for is sometimes <.< but the true answer is always.
But put sometimes.

Answer 5

Joe is right if u use the quadratic equation technically u found the roots so u can use it to factor the equation. but yea put sometimes

Answer 6

The answer is C) Sometimes


Consider the quadratic equation x^2+5x+6=0, we can factor the left side into (x+2)(x+3).


However, the quadratic equation x^2+3x+7=0 cannot be factored (over the rationals), but it can be solved using the quadratic formula.

Answer 7

Thanks !

Answer 8

true but the problem ddnt say over rationals so u could argue this 1 is what we were saying

Answer 9

well my experience is when they say "factor" they mean "over the rationals" (at least with high school that is). Ie, find two rational numbers p and q such that ax^2+bx+c=(x-p)(x-q), but you have a point jahtoday.

Answer 10

you should tell your teacher this is a trick question
i think she would mean factor over rationals but it doesn't say that

Answer 11

anything can be factored but it would be hard to get some of those factors that factor over the real/complex without using quadratic
but i think it is possible with enough trail and error lol

Answer 12

you know without using the quad formula

Answer 13

if someone asked me what x^2+3x+7 factored into, i would answer:
\[(x-\frac{-3-i \sqrt{19}}{2})(x-\frac{-3+i \sqrt{19}}{2})\]
>.>

Answer 14

lol

Answer 15

see its easy lol

Answer 16

yes thats what i would say to joe without using quadratic formula
its an easy guess right saifoo?

Answer 17

Myinin, v both are going with same Pace, i just checkd.

Same Level. Same Medals! :D

Answer 18

lol

Answer 19

Oh Yea it is! :D

Answer 20

hehe.