What is the solution set for |2x – 3| = 11?
Okay well first do u know what abs value means?
no
Whatever in absolute value is always going to be positive itself.
So: |-a|=a |-b|=b, etc.
Now how does that help you?
so its gonna be 2x+3=11?
For solving equations with absolute values there's a very nice rule that might help you out.. \[|a| = b \implies a = b \text{ OR } a = -b\] So in your example here, what is our 'a' and what is our 'b'?
That and what else? Keep in mind that whatever inside abs values, can also be negative.
*whatever is inside
You will get 2 equations, that one you have is the first. The second possibility is that the stuff inside the absolute value equals -11. So solve both equations and you will have your solutions.
so your inside can either be negative 11 or positive 11
see, they don't answer questions. so you go elsewhere, and come back when/if they do.
Smart polpak, let's get out of here
if u were given |x|=10 then x=-10 or 10 this is because the absolute value turns the final result of anything that is inside it to the positive value. so when ever u solve an absolute value u have to make 2 equations. so for this 1 u have to solve for 2x-3=11 and 2x-3=-11 both solutions work because of the absolute value
11+3 isnt 13 and if u put -7 into the equation u wont get the right answer
ok. a bit angry when i wrote it . . lol
I could not disagree more Lambert
I'm with Socrates on this one.
aww polpak i was about to read it..
and give a counter example.. =(
I didn't delete it.
i think he deleted it himself
I think Lambert self censored because he was angry when he wrote it.
oh well im out polpak tnx for ur help again!
fck off bahrom and freaking polpak. all i asked for was an answer. i already solved it and i know how to do it. i just wanted to see what others will get so i could compare answers. so if ur not gonna answer, plz leave. ur not the only ones online
Using the definition of absolute value:\[2x-3=11\]\[2x-3=-11\]Add 3 to both sides\[2x=14\]\[2x=-8\] Which gives\[x=7\]or\[x=-4\]
Join our real-time social learning platform and learn together with your friends!