Question

sqrt-64/(7-6i)-(2-2i) and sqrt-10(11+sqrt-5, operations of complex numbers

Answer 1

anybody plz

Answer 2

2 problem?

Answer 3

\[\frac{-62^2}{7-6i}-(2-2i)\]?

Answer 4

sorr 64 not 62

Answer 5

these are two seperate equations not together, sorry if i confused you

Answer 6

click on the bottom rewrite the equation

Answer 7

1# sqrt-64/(7-6i)-(2-2i)
2# sqrt-10(11+sqrt-5, ?

Answer 8

yes

Answer 9

\[\sqrt{-64}\div(7-6i)-(2-2i)\]

Answer 10

\[\sqrt{-10}(11+\sqrt{-5}\]

Answer 11

start second:\[\sqrt{-10}=\sqrt{-1}*\sqrt{10}\]\[\sqrt{-1}=i\]
\[\sqrt{-10}*(11+\sqrt{-5)}\]\[(\sqrt{-1}*\sqrt{10}*11)+(\sqrt{-1}*\sqrt{10}*\sqrt{-1}*\sqrt{5})\]\[(11i \sqrt{10})+(i*i*\sqrt{10}*\sqrt{5})\]\[i*i=i^2=-1\]\[(11i \sqrt{10})+(-1\sqrt{50})\]\[11i \sqrt{10}-5\sqrt{2}\]