Could someone please solve for the RANGE of the following functions? I just want to check if my answers are correct.

Question

anonymous · Answer

attachment

anonymous · Answer

here we go again
1) all real numbers
2) $$(-\infty,1)$$
3) $$(0,\infty)$$

anonymous · Answer

4) 
$$[0,\infty)$$
5)
$$[\sqrt[5]{4},\infty)$$

anonymous · Answer

6) 
$$(-\infty,9)$$

anonymous · Answer

7 takes a bit of work

anonymous · Answer

calc class or something else?

anonymous · Answer

just the answer is fine please :D and not exactly calc class

anonymous · Answer

well i don't know how to do it without calc.  that is why i am wondering. or maybe you could "sovle for y"

anonymous · Answer

ohh, i solved for y :)

anonymous · Answer

wait maybe i mean solve for x.

anonymous · Answer

really the way i know how to do this is to take the derivative, set = 0 and solve for x. then put that number back in the function and find the y value. lt is ugly. lets get some help

anonymous · Answer

i got [0, positive infinity) does it make sense?

anonymous · Answer

i mean, the lowest possible value for x^2 would be 0 and for sqrt of x, it would be 0 too... right?

anonymous · Answer

the problem is that on 
$$(1,1) $$ 
$$x^2<\sqrt{x}$$ so on that interval answers will be negative

anonymous · Answer

i mean on the interval 
$$(0,1)$$