Question

Perimeter of the equilateral triangle ABC is 72 and the perimeter of the isosceles triangle DBC with the base BC=24 is 50. Which is AB + BD?
Answer 37
31
27
23

Answer 1

Since ABC is equilateral, then all sides are equal so AB = BC = AC = 24.

The isosceles triangle has two sides that are equal BD and CD so 2 times those lengths + 24 = 50

2x + 24 = 50
2x = 26
x = 13 = BD = CD

So AB + BD = 24 +13 = 37

Answer 2

can you help me on my last question?

Answer 3

Which question?

Answer 4

hld on

Answer 5

Perimeter of the rhombus MNPQ is 48 and the perimeter of the parallelogram NPRS, which has a common side with the rhombus, is 60. Which is the difference between two distinct sides of the parallelogram?
Answer 10
9
8
6

Answer 6

Okay, so since it's a rhombus we know all four sides are the same length. So we know that the common side with the parallelogram is equal to 48 /4 = 12. The opposite or facing sides of a parallelogram are equal, so we know that two of the sides as 12 and 12 = 24. That leaves us with 60 - 24 = 36. 36 / 2 sides = 18. The difference between the sides of the parallelogram are then 18 - 12 = 6.

Answer 7

Area of the square P is 36 square inches and the perimeter of the rectangle R is 144 inches. If a width of the rectangle is two times a length of the square, which is the length of a length of the rectangle?
Answer 70
60
45
30

Answer 8

can u help me on this one to?

Answer 9

Okay, the area of the square = 36. A = s x s so the side of the square is equal to 6.

The width of the rectangle is 2 times the length of the square so the width = 12.

2 x length + 2 x width = perimeter of rectangle

2l + 2(12) = 144
2l + 24 = 144
2l = 120
l = 60

Answer 10

thank you so much

Answer 11

No problem. Helpful to know the properties and equations of area and perimeter of geometric figures.