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Mathematics 13 Online
OpenStudy (anonymous):

Simplify: xyz / (xy + yz + xz)

OpenStudy (anonymous):

1/x+y

OpenStudy (anonymous):

can you explain how you got that answer please?

OpenStudy (anonymous):

is it correct?

OpenStudy (anonymous):

xyz/xy+yz+xz=z/yz+xz=z/1*1/yz+xz=z/yz+xz=1/x+y

OpenStudy (anonymous):

make sense?

OpenStudy (anonymous):

Not really... I seems as though you canceled xy to get z/yz+xz but I thought that you can only cancel factors not terms

OpenStudy (anonymous):

is the answer right?

OpenStudy (anonymous):

I don't know.

OpenStudy (anonymous):

Oh, then i'm not sure

OpenStudy (anonymous):

i just

OpenStudy (anonymous):

divided like terms throughou

OpenStudy (anonymous):

there is nothing to "simplify"

OpenStudy (anonymous):

you cannot divide term by term

OpenStudy (anonymous):

need to know the answer to verify whom has correct approach

OpenStudy (anonymous):

You have that \[\frac{xyz}{xy+yz+xz}=\frac{xyz}{x(y+z)+yz}\] You can are correct that you can only cancel factors and not terms. Hence, although i have simplified the denominator slightly, there is no one common factoor on teh denominator and so no cancellation can occur. An example of where you can cancel terms would be \[\frac{xyz}{xy+yz+xz}=\frac{2xy}{xy+xz}=\frac{x(2y)}{x(y+z)}=\frac{2y}{y+z}\] Hope that clarifies matters for you

OpenStudy (anonymous):

Sorry, how did you get \[2xy / xy + xz\] ?

OpenStudy (anonymous):

OOPS! in the second equation/fractions I was trying to show you a DIFFERENT example of how factoring works, and I had copied and pasted. I did not mean to have the first fraction there but rather only \[\frac{2xy}{xy+xz}=\frac{2y}{y+z}\] For your particular question, I do not see any way of simplifying beyond what you originally gave. Sorry

OpenStudy (anonymous):

oh ok. Thank you

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