Question

7x^2-13y=0 ; solve for X

Answer 1

u ther?

Answer 2

yeah

Answer 3

k, cool.

Answer 4

7x^2 = 13y

Cross multiply

x^2 = \[\frac{13y}{7}\]

Answer 5

well, it says the answer should be: x=±√91y/7

Answer 6

Put roots to cancel square:

FInal Answer:

\[\sqrt{\frac{13y}{7}}\]

Answer 7

it cant be 91.

Answer 8

hm...I think I'm supposed to do something like let U= blah and U^2= Blah or something...

Answer 9

umm, nope.

Answer 10

my notes say take an equation that is not quadratic and write it in to equivilant quadratic form then use quadratic forumla to find solutions. But, I don't think this is one of those problems

Answer 11

Im quite confused about it >.< but that is the answer my teacher had there? maybe he is wrong!

Answer 12

lol, your notes are confusing u + they are confusing me too!

Answer 13

well, it is a test review, so it doesn't say which part of my notes to use. But there is a section of the test lower that asks me to do what I said above, so I don't think this is that. and when I worked it myself, I got what you got. I wonder if he just put the wrong answer?

Answer 14

Might Be.

Answer 15

will you help me with this one instead: \[\sqrt{a^2+b^2}=C ;a\]

Answer 16

solve for a

Answer 17

it was supposed to space out. it's =c (solve for a)

Answer 18

Oh, okay!
got that. :)

Answer 19

:)

Answer 20

\[\sqrt{C^2 - b^2 }\]

Answer 21

how did you get that?

Answer 22

\[a = \sqrt{C^2 - b^2 }\]

Answer 23

well, can u join me on twiddla? i can show u the working there!

Answer 24

twiddla? Ive never heard of it. lemme see

Answer 25

http://www.twiddla.com/578717