So if you have x to the 1/3 power plus x to the 2/3 power, that would = x to the 3/3 power, right?
They gave you \[x^{1/3} + x^{2/3} \] and they want you to do what?
add them, inside parentheses....
I'm assuming anyway...there's a plus sign between the two inside parentheses...and the stuff in parentheses is then brought to the second power..
I'm probably not making any sense here..
No, you're not. What parentheses?
\[x^{1/3}(1+x^{1/3})\]
\[(x ^{1/3} +x ^{2/3})^{2}\]
I finally typed something using the equation editor! :D
That's the right equation I just posted..
Where did the squared come from?
You mean the 2 outside the parenthesis?
That wasn't in the original post
I see what to do now
oops..
You have to multiply
\[(x^{1/3} + x^{2/3})*(x^{1/3} + x^{2/3})\]
But what about the addition inside the parentheses? Do I just do the addition inside, or do I multiply the x values inside together, also? If I do add the stuff inside, how will their exponents turn out?
I will show you....I'm going to post a classroom
ok then..
http://authorlive.com/aliveext/LoginToSession.aspx?SessionCode=CnPpSZN%2bKFDYx%2feVKH8dCw%3d%3d
Where are you?
I have not recieved your thing in my e-mail yet..
I posted the link above
I'm assuming that's where you'd post it..
It's above
i think answer is x+x^2
It's not
I already explained the answer
could also be written as cuberoot of x + (cuberoot of x)^2
which is x+x^2
not sure if your answer is right either hero boy
My answer is correct...you didn't see it because you weren't invited to my class
oh my
touchy subject for you?
you hold classes?! wow
prove it
Okay
can you prove your answer is right?
http://authorlive.wiziq.com/aliveext/logintosession.aspx?SessionCode=BorkqON9Qdsqfl0XXHyfyA%3d%3d
Yes
no
What's the matter? You don't like my classroom?
i'm just kidding
I can still show you that my solution is correct, you'll just have to wait your turn
what teaching credentials do you posess?
All of them
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